Convert 1.2 times 10^-3 to decimal notation. 1.200 0.1200 0.0120 0.0012 What is
ID: 1626347 • Letter: C
Question
Convert 1.2 times 10^-3 to decimal notation. 1.200 0.1200 0.0120 0.0012 What is 0.674/0.74 to the proper number of significant figures? 0.91 0.911 0.9108 0.9 what is the sum of 1123 and 10.3 written with the correct number of significant figures? 1.13 times 10^3 1133.3000 1.1 times 10^3 1133.3 1133 The length and width of a rectangle are 1.125 m and 0.606 m, respectively. Multiplying, your calculator gives the product as 0.68175. Rounding properly to the correct number of significant figures, the area should be written as 0.7 m^2. 0.68 m^2. 0.682 m^2. 0.6818 m^2. 0.68175 m^2. Which of the following quantities has units of a displacement? (these could be more than one correct choice.) 32/s^2 vertically downward 40 km southwest 9.8 m/s^2 -120 m/s 186,000 mi Suppose that an object travels from one point in space to another. Make a comparison between the magnitude of the displacement and the distance traveled by this object. The displacement is either greater than or equal to the distance traveled. The displacement is always equal to the distance traveled. The displacement is either less than or equal to the distance traveled. The displacement can be either greater than, smaller than, or equal to the distance traveled.Explanation / Answer
Ans 1 d part is correct 1.2×10^-3 =0.0012 count from decima,l no is 3 so power wil be -3
Ans 2 0.674/0.74=0.91because in multiplication Final Result should retain as many significant fig as are there in orignal no With least significant figures least significant fig in this Q is 2 so ans wil be upto 2 significant fig
ANS 3 1123+10.3 = 1133 because in sum final result should retain As decimal places As are there in no with Least decimal places
Ans4 0.682m^2 using rule given in ans 2
Ans 5 B 40 Km southwest dispacement has direction in it with value
Ans 6 C displacement is either less than or equal to distance travelled because distance is actual path covered and displacement is shortest path between initial and final position
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