Contrvelocity h…n erreleindon of 0 Question 4-4: The diagram below shows positio

Question

Contrvelocity h…n erreleindon of 0 Question 4-4: The diagram below shows positions of the cart at equal time in- tervals. (This is like overlaying snapshots of the cart at equal time intervals. The motion detector also looks at the cart's position at equal intervals.) At each indi- cated time, sketch a vector above the cart that might represent the velocity of the cart at that time while it is moving at a constant velocity away from the motion detector. Assume that the cart is already moving at t. 4 =4 = 1s Motion Detector x1 x2 Positive x direction Comment: To find the average acceleration vector from two velocity vectors, you must first find the vector representing the change in velocity by subtract- ing the initial velocity vector from the final one. Then you divide this vector by the time interval. Question 4-5: Show below how you would find the vector representing the change in velocity between the times 2 and 3 s in the diagram in Question 4-4. (Hint: The vector difference is the same as the sum of one vector and the nega- tive of the other vector.) From this vector, what value would you calculate for the acceleration? Explain. Is this value in agreement with the acceleration graph or the previous page? LAB 1: INTRODUCTION TO MOTION

Explanation / Answer

We know that the cart is moving along the horizontal direction.Let the direction towards right be positive x axis. Velocity at t=2 seconds is v2 i and velocity at t=3 seconds is v3 i . Therefore difference in velocity = v3 i - v2 i = (v3-v2)i

it will be a vector with magnitude of (v3-v2) drawn along x axis

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