Chrome Fle Edit View History Bookmarks People Window Help 21 HW Secure hetps Ch.
ID: 1629106 • Letter: C
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Chrome Fle Edit View History Bookmarks People Window Help 21 HW Secure hetps Ch.21.HW Pat Carnot Cydle: Just How Ideal Is ? ysics.com/myemViewtassignmentProblemiD 785969118offsetsnext Camot Cycle: Just How Ideal Is It? Part A Learning Goal: n general tems, the eficiensy of a syatem can be thought of as the output per unit input Which of the expressions is a good mathematical ropresentation of ficiency of any heat engine? To understand the quanttative relationships related to ideal Camol) engines and the limitations of such devices imposed by the seoond law of thermodynamics In 1824, Sadi Camot, a French engineer, introduced a theoredical then called a Camot he most efficient engine possible. The following statement is known as Camots theomm No engine operating between a het and a cold reservoir can be more officient than the Camot engine that rgro that operat operateos between the beteen the The Camot ergine is a threoretical enginge with the maximum possble eficieney, somewhat lke a heught experiment S Camot engine operates eyclicaly, jute any real engine. The Camot cyole includes four reversible seps: two isothermal processes and two probiem, you will be asked several questions about Camot engines. We will use the following symbols Q.: the absolute value (magnitude) of the heat absorted from the hot neservailr during one cycle or Qa thre absolule value (magnitude) of the delivered to the oold reervoir during one cydle or he amount of work done by the engine during O Increases one cycle or during some trna spored r T:the absolule temperature of the hot reservoir To: the absolute temperature of the oold nl emains constant My Answers Give Up Part C Which of the following gives the officiency of the Camot engine? MacBook ProExplanation / Answer
A) W/Qin
B) remains constant
C) (Tin - Tout)/Tin
D) 0.545
E) The carnot engine has zero power
F) Recall that in a Carnot cycle,
Qout/Qin = Tout/Tin,
Also, W = Qin - Qout
Wmax = (Tin/(Tout -1) x Qout
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