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A force in the +x-direction with magnitude F(x)=18.0N(0.530N/m)x is applied to a

ID: 1629119 • Letter: A

Question

A force in the +x-direction with magnitude F(x)=18.0N(0.530N/m)x is applied to a 7.50 kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box.

MasteringPhysics HW 6-Google Chrome i Secure https://session.masterin HWEExercise 6.49 Enhanced-with Solution ?assignment Problem!D= 78999544 s previuus 10 of 10 etuir lo assigumer Exercise 6.49 Enhanced with Solution Part A force in the +z-direction with magnitude it 1he ho× is, initially at rest at ¢-0, what is its speed amer it has traveled 15 () m ? ) 18.0NH(0.530 N/m)r is applied to a 7.50 kg box that is tting on the horizontal, trictionless surtace ot a trozen lake 1(r) ts he onty horizontal force on the box Express your anewer to three aignificant figures and include the appropriate units. You may want to rewiew pages 183-1a) Hor related problemsoliving tips and strategies, you may want to viewa Video Tutor Solution of Motion with a varving force v7.975 m Submit Incorrect; Try Again; 5 attempts remaining Provide eedback

Explanation / Answer

here,

F(x) = 18 N - 0.53 x

work done , W = integration(F.dx)

W = 18 x - 0.265 x^2

at x= 15 m

W = 18 * 15 - 0.265 * 15^2

W = 210.4 J

let the final speed be v

kinetic energy gained = work done by force

0.5 * m * v^2 - 0 = 210.4

0.5 * 7.5 * v^2 = 210.4

v = 7.49 m/s

the final speed is 7.49 m/s

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