I\'m in electricity and magnetism physics. I am having trouble understanding thi

Question

I'm in electricity and magnetism physics. I am having trouble understanding this problem. Can you please explain each step. And show how to check this problem. Thank you
U) What energy is stored in the capacitor? Variation of 16.65: a) Capacitors Ci-6quF and C tors C-6uF and C 2uF are charged as a parallel combination across a 250-volt battery. The capacitors are disconnected from the battery and from each other. They are then connected positive plate to negative plate and negative plate to positive plate. Calculate the resulting charge on each capacitor. b) What happens i Chapter 17 Problems Variation of 17 S1 Coneidor an utm if Ci and C were originally connected in series to the 250-volt battery? The disconnecting and reconnecting is the same. What is the resulting charge on each capacitor?

Explanation / Answer

Given,

C1 = 6 x 10-6 F, C2 = 2 x 10-6 F, V = 250 V

a) Capacitors are charged in parallel, so both are at 250 V when they are disconnected from the battery.

Then charge on each capacitor:
Q1 = 6 uF x 250 V = 1500 uC
Q2 = 2 uF x 250 V = 500 uC

Let assume this as 1500 uC of excess negative charges on one plate, and 1500 uC of excess positive charges on the other plate.

When the positive plate of C1 is connected to the negative plate of C2, and the negative plate of C1 is connected to the positive plate of C2, some of these excess opposite charges will combine and cancel each other.

The result is that 1500 uC - 500 uC = 1000 uC of charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 1000 uC will be divided proportionately between the two capacitors.

Q1 new = 1000 uC x (6/(6+2)) = 750 uC
Q2 new = 1000 uC x (2/(6+2)) = 250 uC

The resulting voltage, V = Q1/C1 = Q2/C2 = 750/6 = 125 V

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