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Secure https://session.masteringphysics.com/myct/itemview?assignmentProblemID-78596744&offset; next Ch 19 HW Part2 Problem 19.23 previous | 2 of 10 next Problem 19.23 Part A A cube can be envisioned as an assembly of identical octants (numbered 1-8 in no particular order). The cube contains four identical particles. How many basic states in this system yield a macrostate in which all four particles are in octant 1? N 1 state(s) Submit My Answers Give Up Correct Part B How many basic states in this system yield a macrostate in which two particles are in octant 8 and the remaining partcles are in the other octants? N- 7 state(s) Submit My Answers Give Up Incorrect, Try Again; 5 attempts remaining

Explanation / Answer

As 2 of the particles are in octant 8 and rest of the two are in the other octants. So along with the 2 particles in octant 8

Remaining two may be together and can be found in octants 1 to 7. As they are indistinguishable so we can assume them as single particle and no. of ways to distribute 1 particles in 7 boxes are 7C1 = 7.So possible basic states are 7 for this case.

Remaining two are not together. No. of ways to distribute 2 particles in 7 boxes are 7C2 = 21.So possible basic states are 21 for this case.

Hence total no.of cases are 7+21 = 28.

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