I already did most of the work for part A, just getting the wrong answer. So, he

Question

I already did most of the work for part A, just getting the wrong answer. So, here's the question and work I've done for part A:

At a certain location, the Earth's magnetic field has a magnitude of 5.4*10^-5T and points in a direction that is 68 degrees below the horizontal. Find the magnitude of the magnetic flux through the top of a desk at this location that measures 76cm by 45cm.

earths magnetic field B =5.4 * 10-5 T

area A = 76 cm * 45 cm

            = 3420cm2

            = 3.420 m2

angle = 90 - 68degrees = 220

therefore ,magnetic flux is

      B = B.ds

          = BA cos(220)

So, I just need to know how to finish this with steps, since I keep getting it wrong.

Part B:

Explanation / Answer

magnetic flux is phi = B*A*cos(theta)

here theta is the angle between magnetic field B and area A of the desk

cos(90-68) = cos (22)

so magnetic flux is phi_B = B*A*cos(22) = 5.4*10^-5*0.76*0.45 = 1.85*10^-5 Wb

Part B)

1) current i = emf / R = (B*L*v)/R

2) speed is v = i*R/(B*L) = (1*R)/(B*L) = R/(B*L)

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