IP A person holds a 1.34 N baseball in his hand, a distance of 34.0 cm from the
ID: 1630111 • Letter: I
Question
IP A person holds a 1.34 N baseball in his hand, a distance of 34.0 cm from the elbow joint, as shown in the figure(Figure 1) . The biceps, attached at a distance of 2.75 cm from the elbow, exerts an upward force on the forearm. Consider the forearm and hand to be a uniform rod with a mass of 1.20 kg. Suppose the biceps exert just enough upward force to keep the system in static equilibrium.
Part A
Is the force exerted by the biceps more than, less than, or equal to the combined weight of the forearm, hand, and baseball?
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Correct
Part B
Explain.
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Part C
Determine the force exerted by the biceps.
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Figure 1 of 1
IP A person holds a 1.34 N baseball in his hand, a distance of 34.0 cm from the elbow joint, as shown in the figure(Figure 1) . The biceps, attached at a distance of 2.75 cm from the elbow, exerts an upward force on the forearm. Consider the forearm and hand to be a uniform rod with a mass of 1.20 kg. Suppose the biceps exert just enough upward force to keep the system in static equilibrium.
Part A
Is the force exerted by the biceps more than, less than, or equal to the combined weight of the forearm, hand, and baseball?
more than less than equal toSubmitMy AnswersGive Up
Correct
Part B
Explain.
Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
3800 Character(s) remaining
SubmitMy AnswersGive Up
Part C
Determine the force exerted by the biceps.
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Provide FeedbackContinue
Figure 1 of 1
Humerus Biceps Radius Ulna 2.75 cm Mg 17.0 cm 170cm 17.0 cmExplanation / Answer
part B
SInce elbow is too close to biceps ,the force exerted by biceps will be more than the comboned weight of arm and ball.Below is the scientific calculation of force exerted by elbow
Let the force supplied by biceps be x N
SInce it is in equilibrium
net force=0
net torque=0
let force supplied by elbow is y N
x+y=1.34+(1.2*9.8)=13.1 N
writing torque equation about elbow
x*2.75-(1.2*9.8*17)-(1.34*34)=0
we got x=89.3 N
part C
=89.3 N
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