A 525-N physics student stands on a bathroom scale in an 846-kg (including the s
ID: 1632094 • Letter: A
Question
A 525-N physics student stands on a bathroom scale in an 846-kg (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 499 N .
a - Find the magnitude of the acceleration of the elevator.
b- Find the direction of the acceleration of the elevator.
c- What is the acceleration if the scale reads 619 N ?
d-If the scale reads zero, should the student worry? Explain.
What is the tension in the cable in part A?
What is the tension in the cable in part D?
Explanation / Answer
a. 525 = m*g = m*9.81
m = 525/9.81 = 53.52 kg
499 = m(g - a)
g-a = 499/m
a = g - (499/m)
a = 9.81 - (499/53.52) = 0.486 m/s^2
b. direction is downwards
c. 619 = 53.52(9.81 + a)
9.81+a = 619/53.52 = 11.565
a = 11.565-9.81 = 1.755 m/s^2 upwards
d. The scale reads 0,
The accelerator is in free fall.
Yes, there is reason to worry
e. Tension, T = mg-ma
T = 846*9.81 - 846*0.486 = 7888.10 N
f. Tension, T = mg + ma
T = 846(9.81+1.755) = 9784 N
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