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Chrome File Edit View History Bookmarks People Window Help 0 a Q O R ) E 93% D. Fri Jul 21 4:46 PM Nawaf Q IE ... de Mei w x 6 x 9 mo x 2 core x Mei x 7, 17 x 1, Das x , coux C sig x O wo xa (x R Des x C Pny XC Pny xo e H C o www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=3805088 Q & O GORRU Due Date: 7/21 A Sapling Learning Map Points Possible: 100 100 A trapeze artist performs an aerial maneuver, while in a tucked position, as shown in Figure A, she rotates about her center of mass at a rate of 5.55 radls. Her moment of inertia about this axis is 18.5 kg m?. A short time later the aerialist is in the straight position, as shown in Figure B. If the moment of inertia about her center of mass in this position is now 34.3 kg m?, what is her rotational speed? Grade Category: Grac Description: Policies: Rub Number rad/s You can check your answ You can view solutions at You can keep trying to ar you get it right or give up There is no penalty for in For multiple-choice ques on the number of choice O eTextbook Figure A Figure 8 o Help With This Topic Web Help & Videos o Technical Support and O Previous O Check Answer O Next al Exit a PHYS 211 A Exam I...docx - L Show AIX 19 A g o o CD o EPO @ & gs N POF WAGS LTTENTU

Explanation / Answer

According to the given problem,

This is conservation of angular momentum problem.
Angular momentum = I *
Initial = 18.5 * 5.55 = 102.675
Final = 34.3 * f
34.3 * f = 102.675
f = 2.99344
This is approximately 3 rad/s.

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