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Chrome File Edit View History Bookmarks People Window Help 0 a Q O R ) E 90% OFr

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Question

Chrome File Edit View History Bookmarks People Window Help 0 a Q O R ) E 90% OFri Jul 21 4:55 PM Nawaf Q IE lex a w x 0 x 0 me x Cox 8 Mex on 17 x in Da x Cox G sle x O w x Tax R Dex G Pn X G anx G on a M – C o www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=3805088 Q AO : Jump to.. McNeese State University - PHYS 211 - Summer17-STINNETT Activities and Due Dates HW: Dynamics of Rotational Motion Resources Attempts Score O 7/21/2017 10:00 PM 0 20/100 O 7/19/2017 03:12 PM D Gradebook O Assignment Information e Print A Calculator - Periodic Table Question 4 of 10 X incorrect X incorrect XI Available From: 7/15/2017 02:00 PM Due Date: 7/21/2017 10:00 PM A Sapling learning Points Possible: 100 A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are 0.705 m and 1.01 kg. What constantmagnitude force acting at the other end of the rod perpendicularly both to the rod and to the axis will accelerate the rod from rest to an angular speed of 6.35 radls in 8.57s , Grade Category: Graded Description: Policies Rubric 1 Number You can check your answers. You can view solutions after the due date. You can keep trying to answer each question until you get it right or give up. There is no penalty for incorrect answers. For multiple-choice questions, the penalty depends on the number of choices available. OeTextbook o Help With This Topic a PHYS 211 A Exam ...docx - L Show AIX OF @0 OS CD W ROM i s N OB SOAGEROEDENT

Explanation / Answer

length of rod(L)=0.705m

mass ogf each rod(m)=1.01kg

time(t)8.57sec

w1=0

w2=6.35rad/seconds

moment of inertia about the end is =ml^2/3

i(w2-w1)(1/t)=lxF

(1.01x0.705^2(1/3))(6.63)(1/8.57)=(0.705)F

F=0.18362N

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