In the future people will only enjoy one sport: Electrodisc. In this sport you g

Question

In the future people will only enjoy one sport: Electrodisc. In this sport you gain points when you cause metallic discs hovering on a field to exchange charge. You are an Electrodisc player playing the popular four disc variant. The disks have charges of qA = 8.0 µC, qB = 2.0 µC, qC = +5.0 µC, and qD = +12.0 µC.

(a) You bring two disks together and then separate them. You measure the resulting charge of these two disks and find that it is +8.5 µC per disk. Which two disks did you bring together?

A and B

A and C     

A and D

B and C

B and D

C and D

(b) You bring three disks together and then separate them. You measure the resulting charge of these three disks and find that it is +3.0 µCper disk. Which three disks did you bring together?

A, B, and C

A, B, and D    

A, C, and D

B, C, and D

(c) Given the resulting charge of each disk measured in (b) is +3.0 µC, how many electrons would you need to add to a disk of this charge to electrically neutralize it?

Explanation / Answer

Given that
qA = -8.0 uC
qB = -2.0 uC
qC = +5.0 uC
qD = +12.0 uC

all you have to do for these problems is find the average between two of the rods

(1)
qC = +5.0 µC and

qD = +12.0 µC

5+12 = 17

17/2 = 8.5

so rods C and D

(2)
-8+5+12 = 9

9/3 = 3

so rods A, C, and D

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