If I_1 goes to the right through R_1, I_2 goes to the right through R_2, and I_3

Question

If I_1 goes to the right through R_1, I_2 goes to the right through R_2, and I_3 goes to the right through R_3. what is resulting equation resulting from applying Kirchhoff's 1 clockwise loop around the s Loop rule for a the circuit? 8.0 V + I_1R_1 + I_3R_3 = 0 -8.0 V + I_1R_1 - I_3R_3 = 0 -8.0 V + I_1R_1 + I_3R_3 = 0 8.0 V + I_1R_1 - I_3R_3 = 0 8.0 V - I_1R_1 + I_3R_3 = 0 A proton moving with a speed of 10 times 10^5 m/s perpendicular to a uniform magnetic field of 1.7 T will follow which of the paths described below (q_p = 1.6 times 10^-18 C and sp = 1.67 times 10^2 kg) a circular path of 1.93 ? radius a straight line path a circular path of 2.904 ? radius a circular path of 0.613971 cm radius a circular path of 3.91 cm radius

Explanation / Answer

19. The correct option is E: 8V -I1R1+I3R3 since going clockwise when you encounter -ve terminal of battery then use positive sign and when encounter resistor in direction of current then use negative. But when current opposite to direction we move then use positive.

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