A. Downward B. Upward C. Leftward D. Rightward E. There is no magnetic force on

Question

A. Downward B. Upward C. Leftward D. Rightward E. There is no magnetic force on the loop An increasing magnetic field is 55.0 degree clockwise from the vertical axis, and increase form 1.20 T to 1.44 T in 3.80 s. There is a coil at rest in the horizontal plane and it has 800 turns and a diameter of 5.00 cm. What is the induced emf? A. 7.11 times 10^V B. 0.0813 V C. 0.341 V D. 0.0569 V E. 0.0992 V A 14.0 cm diameter loop with a resistance of 0.300 Ohm is in a magnetic field increasing at 0.900 T/s as shown in the image. What is the magnitude of the induced current? A. 0.0154 A B. 0.0139 A C. 0.185 A D. 0.420 A E. 0.0462 A

Explanation / Answer

a) It should be leftward

b)EMF = N dphi /dt

dphi= Acos theta ( dB)/ dt

A= pi r^2 = (3.14) (0.000625) =0.0019625 m^2

dhi/dt = 800 ( 0.0019625 ) (1.44-1.20)/ 3.80 = 0.0992 V apprx

Q.3: E = dphi/dt = A dB/dt = 3.14 (0.0049 ) (0.9) = 0.0138474 V

I = E/R = 0.0462 A apprx

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