A double-slit experiment with electrons is arranged so that the electron source

Question

A double-slit experiment with electrons is arranged so that the electron source emits only one electron, and only after the previously emitted electron has been already detected, after passing through the double-slit screen. In that way, only one electron may be present in the experimental setup, anywhere between the electron source and the electron detection surface. The experiment is repeated a million times. Which of the following is correct: a. The interference pattern will be observed already for each individual electron, because it is physically dissociated into many little fragments that fall all over the detection screen. b. Since it is impossible to have two electrons at the same time present in the experiment, no interference pattern will be observed on the detection screen. c. The interference pattern will be observed as a pattern of hits of the individual electrons over the detection screen. d. No pattern may be observed because Planck's black-body formula has not been fully satisfied.

Explanation / Answer

Correct option is A because by Heisenberg uncertaintity principle we can't tell through which slit electron will pass..Hence a interference pattern will be observed due to dual natural of electron I.e we can consider electron as a wave associated with it whose wavelength is given by debroglie hypothesis,hence can consider it to be divided into fragments,,,for interference pattern to be observed spacing between slits should be very small

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