75 g of boiling water is added to 300 g of unknown liquid of temperature 50 degr

Question

75 g of boiling water is added to 300 g of unknown liquid of temperature 50 degree C. After stirring the two liquids, the final temperature is found to be 80 degree C, where the specific heat of water is 4.184 J/g degree C. Approximating the two-liquid mixture as a closed system, determine the specific heat of the unknown liquid. Here's how you do it: -Q_w = Q_u -m_wc_w deltaT_w = m_uc_u delta T_u c_u = - m_w c_w delta T_w/m_u delta T_u c_u = - m_w c_w delta T_w/m_u delta T_u Now plug in your numbers 200 g of ice are added to 700 g of boiling water. The latent heat of fusion for water/ice is 334 J/g. Determine the final temperature of the mixture if it were a closed system. Here 's how you do it: - m_wc_w deltaT_w = m_ic_w delta T_i + Lm_i -m_wc_w(T_f - 100 degree C) = m_ic_w(T_f - 0 degree C) + Lm_i T_f(m_wc_w + m_ic_w) = 100 m_wc_w - Lm_i T_f = 100m_wc_w - Lm_i/c_w(m_w + m_i) Now plug in your numbers

Explanation / Answer

Solving first question of the page

Q10

putting all the values

we get

c=0.4184 J/gK

Q11

again putting all the values

c=59.98 C

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