If 6.0 joules of work is done to move 2 coulombs of charge from point A to point

Question

If 6.0 joules of work is done to move 2 coulombs of charge from point A to point B, what is the electric potential difference between points A and B? a) 6.0 volts b) 0.33 volts c) 0.66 volts d) 3.0 volts e) 12.0 volts Charge A is +2.0 times 10^-6 coulombs and charge B is +1.0 times 10^-6. If e force that charge A exerts on charge B is +1.0 times 10^-2 newtons, then the force that charge B exerts on charge A in newtons is a) +1.0 times 10^-2 b) +2.0 times 10^-2 c) 3.0 times 10^-2 d) +5.0 times 10^-1 e) 1.0 Base your answers on questions 4 and 5 on the following diagram which represents an alpha particle moving toward point A moving at a constant speed of 2 m/s perpendicular to a uniform magnetic field between the poles of a magnet emitting a magnetic field of 0.1 webers per square meter: The direction of the magnetic force on the alpha particle is towards: a) A b) B c) C d) D e) Santa's House The magnitude of the magnetic force on the alpha particle is 3.2 times 10^-20 b) 6.4 times 10^-20 m c) 0.1 m d) 0.2 m e) 2 m

Explanation / Answer

Using

V = W/Q

Where

V is voltage

W is work done

Q is charge

Substituting values

V = 6/2 = 3V

Hence answer is option d

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