could you please answer question 1 and 2 thanks ! appears linear (to within expe
ID: 1638675 • Letter: C
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could you please answer question 1 and 2 thanks !
appears linear (to within expected experimental error) then a linear equation such as r = A + Bn would the data. A computer work sheet Excel or Quattro Pro would allow you to find the intercept A and slope for this equation. You could also calculate the slope from the ratio of rise to run with a calculator. This process of fitting a straight line to data is called linear regression. In many situations the data are not linear and this may not be entirely obvious from simply looking at the graph. A power law such as tau = An^B may instead fit the data. Accordingly, we will use tau = An^B as a mathematical model. We take logarithms on both sides of this equation and simplify it to obtain log tau = log(An^B) = log A + log(n^B) = log A + B log n. If a power law equation such as tau = An^B fits the data, then a graph of log tau vs. log n should be a straight line with slope B, the power of n, and intercept log A, the log of the coefficient of n. Include a graph of log tau versus log n with your report along with your estimate of the A and B values. Once a standing wave appears in the string with several nodes, what would happen if you were to carefully hold the string with narrow tweezers at a node (a geometric point)? Will the standing wave pattern change or be destroyed? On some stringed instruments, strings of different diameters create low frequency sounds and high frequency sounds. What can you say about the relationship between string diameter and sound frequency? Estimate the errors in measuring L, n, and m_s. Discuss how these errors might affect the results. Are there any significant indications of error in your results? Derive an equation for standing wave frequency f from equations (1) and (2).Explanation / Answer
1. If you hold at the position of a node the wave patterns will remain unaffected, because in a standing wave pattern nodes are the points where displacement is zero or amplitude is zero.
2. The relationship between frequency of sound produced and diameter of the string of the instrument involves the factor of spring. A thicker string means more diameter that leads to more mass and also more tension which ultimately results in lowering of number of nodes or you can say that it results in to lower frequency.
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