Need help on this question, it\'s a bit longer because it\'s a 3 part problem. T

Question

Need help on this question, it's a bit longer because it's a 3 part problem. Thanks!

large uniform butcher block and has a weight hanging mass of 101 kg and a length of 2.00 meters. If L 170 meters and the hanging weight is 128 newtons, what is the force on the rests on two supports from its end. The block has a Units Units What is the force on the right support? Number left support Number In Problem 4 ifthe mass and and length are constant (the block has a mass of 101 kg and a length of 2 meters) but the hanging weigh 67 newtons, what is the minimum value for Lfor the configuration to remain stable? Units. Number In Problem 4 ifthe mass and and length are constant (the block has a mass of 101 kg and a length of 2 meters) what is the maximum value for the manging weight irL 1.20 meters and the configuration is to remain stable? Number Units.

Explanation / Answer

b) Sum the moments about the left support:
M = 0 = R*1.70m - 101kg * 9.8m/s² * 1m - 128N * 2m
R*1.70m = 1245.8 N·m
R = 732.82 N

a) Sum the vertical forces: L + 732.82N = 101kg * 9.8m/s² + 128N
L = 384.98 N

c) At the threshold, L = 0 N and R = 101kg * 9.8m/s² + 167N = 1156.8 N
0 = 1156.8N * L - 101kg * 9.8m/s² * 1m - 167N * 2m
L = 1.14 m

d) 0 = (989.8N + W)*1.2m - 989.8N*1m - W*2m
0 = 1187.76N·m + W*1.2m - 989.8N·m - W*2m
0.8m * W = 197.96 N·m
W = 247.45 N

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