2A Fliplt Physics Pima Community College l College Physics (al Copy of Mechanics

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2A Fliplt Physics Pima Community College l College Physics (al Copy of Mechanics macmillan learning Unit 6: Prelecture Bridge Problems Problems: Newton's First And Second Laws Deadline: 100% until Wednesday, June 7 at 11:59 PM Problem 19 A locomotive pulls 10 identical freight cars with an acceleration of 2 m/s 1) How does the force between the second and third force between the fifth and sixth cars? (Express cars compare to the your answer significant fisures.) 2.3 You currently have 2 submissions for this question. Only 6 submission are allowed. You can make 4 more submissions for this question.

Explanation / Answer

The given force is pulling 10 identical cars having collective mass "M."
mass = force / acceleration

F = M*a

Since the 10 cars are identical, each has mass
m = M / 10

between 2nd and third

F = 8M*2/10 = 1.6M (Newton)

betwwn 5 and 6th

F = 5M*2/10 = M   (Newton)

force between 2 and 3rd is 1.6 times of force between 5th and 6th car.

2)   b) takeoff velocity v = (2gh)
v = (2 * 9.8m/s² * 0.428m) = 2.896 m/s

acceleration a = v² / 2d = (2.896m/s)² / 2*0.00200m = 2097.198 m/s²

a) t = v / a = 2.896m/s / 2097.198m/s² = 1.38e-3 s = 1.38 ms

c) F = m(g + a) = 12.1e-6kg * (9.8 + 2097.198)m/s² = 0.025494 N = 25.494 mN
d) ratio = 25.494N / (12.1e-6kg * 9.8m/s²) = 215 to 1

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