A box of mass m sliding with an initial speed of v_i on a rough horizontal surfa

Question

A box of mass m sliding with an initial speed of v_i on a rough horizontal surface runs into a fixed spring of elastic constant k, compressing it a distance x_1 from its relaxed position while momentarily coming to rest. Which equation best represents the energy conversion during the process of the box compressing the spring? 1/2 mv^2_i + 1/2 kx^2_1 + W_due to friction with surface = 0 1/2 mv^2_i + W_due to friction with surface = 1/2 mv^2_f - 1/2 kx^2_1 1/2 mv^2_i + 1/2 kx^2_1 W_due to friction with surface = 1/2 kx^2_1 1/2 mv^2_i + W_due to friction with surface = 1/2 kx^2_1

Explanation / Answer

Solution:

Here, The loss of energy will be equal to the work done against friction.Box of mass 'm' sliding on a rough surface stops momentarily to rest by the opposite force(-kx) applied by the spring on it.we need an equation of energy during the process of compression.

Hence;

loss of energy due to friction = Ei - Ef

=> Work done against friction = 1/2 mvi2 - (-1/2 kx12 + 1/2 mvf2).

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.