A 10 kg disk with a radius of 2 meters has several forces applied to it as shown
ID: 1641348 • Letter: A
Question
A 10 kg disk with a radius of 2 meters has several forces applied to it as shown in the sketch. F1 is 46 N and is applied at the edge of the disk, F2 is 7 N is applied at 1/4 the radius from the center of the disk, F3 is 5 N is applied at 3/4 the radius from the center, F4 is 15 N is applied at the edge of the disk, and, lastly, F5 is 9 N and is applied at the edge of the disk at an angle of 23 degrees. If the moment of inertia about the center for the disk is I = 1/2 M R2, what is the angular acceleration about the center of the disk in rad/s2? If the angular acceleration is clockwise, indicate so with a negative sign.
A 10 kg disk with a radius of 2 meters has several forces applied to it as shown in the sketch. F1 is 46 N and is applied at the edge of the disk, F2 is 7 Nis applied at 1/4 the radius from the center of the disk, F3 is 5 Nis applied at 3/4 the radius from the center, F4 is 15 Nis applied at the edge of the disk, and, lastly, F5 is 9 N and is applied at the edge of the disk at an angle of 23 degrees. If the moment of inertia about the center for the disk is l 1/2 M R2, what is the angular acceleration about the center of the disk in rad/s lf the angular acceleration is clockwise, indicate so with a negative sign F3 F2 F4 F1Explanation / Answer
Net torque in the disc about
X = (46*2) - (6*2/7) - (4*2*3/4) + (9*cos 23*2)
= 109.13 Nm (clockwise)
Mass moment of inertia of disc = 0.5*10*2*2
= 20 m/s2
Angular acceleration of disc = 109.13 / 20
= 5.45 rad/s2 (clockwise)
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