A motorist traveling at 60km/hr brakes to a stop in 100m. A) find his accelerati

Question

A motorist traveling at 60km/hr brakes to a stop in 100m. A) find his acceleration assuming it to be a constant b) what would his stopping distance be if his acceleration were a = -g = -9.8m/s^2 c) what is the stopping time in case (a)? Show working lease A motorist traveling at 60km/hr brakes to a stop in 100m. A) find his acceleration assuming it to be a constant b) what would his stopping distance be if his acceleration were a = -g = -9.8m/s^2 c) what is the stopping time in case (a)? Show working lease

Explanation / Answer

Given that

speed v=60 km/hr=16.7 m/s

distance x=100 m

basing on the concept of equation of kinematices

now we find the acceleration

v^2-u^2=2as

acceleration a=0^2-16.7^2/2*100=-1.4 m/s^2

now we find the stoopping distance if acceleration a=-9.8 m/s^2

distance s=0^2-16.7^2/2*-9.8

=14.23 m

now we find the stopping time

stoppig time t=v-u/a=0-16.7/-1.4=11.93 sec

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