Question 22 of 32 Map Sapling Learning system of four particles moves along one

Question

Question 22 of 32 Map Sapling Learning system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity, v4, of particle 4 at 2.99 s, given the following details for the motion of parcs 1, ad 3 Particle 1: m,-1.69 kg, v1(t)=(6.97 m/s) +(0.321 m/sjxt Particle 2: m2-2.81 kg, v2(t)=(7.83 m/s) + (0.609 m/sjxt Particle 3: m3 = 4.61 kg, v3(r) = (7.21 m/s)-(0.447 m/s2)×1 Particle 4: m4-5.03 kg -2.99 s, given the following details for the motion of particles 1, 2 and 3: Number m/s Previous Give Up & View Solution e Check Answer Next ] Exit Hint

Explanation / Answer

Solution:

Here,

As the center of mass is at rest that means the vector sum of the momenta of the system must be zero.

i,e,

m1v1+m2v2+m3v3-m4v4 = 0

=> 1.69(13.4) + 2.81(9.65091)+4.61(8.54653) = 5.03(v4)

=> 79.9185 = 5.03(v4)

=> v4 = 15.88837 m/s

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