To determine the specific heat of an object, a student heats it to 100 degree C

Question

To determine the specific heat of an object, a student heats it to 100 degree C in boiling water. She then places the 54.3 g object in a 153 g aluminum calorimeter containing 118 g of water. The aluminum and water are initially at a temperature of 19.9 degree, and are thermally insulated from their surroundings. If the final temperature is 22 5 degree, what is the specific heat of the object? Express your answer using two significant figures. Referring to the table, identify the material m the object. Beryllium Aluminum Glass Silicon Iron (steel) Copper

Explanation / Answer

Given that

mass m1=0.0543 kg

mass m2=0.153 kg

mass m3=0.118 kg

temperature T1=100 C

temperature T2=19.9 C

finial temperature T3=22.5 C

basing on the concept of thermal properticies of matter

now we find the specific heat of object

m1S1[T1-T3]=(m2S2+m3s3)(T3-T2)

0.0543*S1*[100-22.5]=(0.153*900+0.118*4186)[22.5-19.9]

4.21S1=1642.3

specific heat of the object S1=390.1 J/kg.k

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