A Calculate the height H of the bridge. B Write down the general expression for

Question

A Calculate the height H of the bridge. B Write down the general expression for the position of apple-2 as a function of time. That is, give an expression for y_2(t). C Calculate the speed with which apple-2 was thrown down? A stone is projected at a cliff of height h with an initial speed of 42.0 m/s directed at angle theta_0 = 60.0 degree above the horizontal. The stone strikes at A, 5.50 seconds after launching. A Find the height h of the cliff. B Calculate the speed of the stone just before impact at A C Calculate the maximum height H reached above the ground.

Explanation / Answer

Initial speed of stone =42 m/s

Angle of projection =60degrees

Time taken to reach highest point =(42*sin60)/9.8=3.71 seconds

Remaining time =5.5-3.71=1.79seconds

Maximum height reached =H=(42*sin60)^2/(2*9.8)=67.5m

Height by which stone comes down in 1.79 seconds =0.5*9.8.1.79*1.79=15.7m

Therefore,height of cliff =67.5-15.7=51.8m

Horizontal speed of stone at A=42*cos60=21m/s

Vertical speed of stone at A=9.8*1.79=17.5 m/s

Speed at A=sqrt(21^2 + 17.5^2) =27.3 m/s

Maximu height =67.5m

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