Three boxes are placed on a seesaw. Box #1 (8 kg) is placed at the very end of t

Question

Three boxes are placed on a seesaw. Box #1 (8 kg) is placed at the very end of the left side of the 3.4 m long seesaw. Box #2 (13 kg) is placed at the other end of the seesaw. The pivot point of the seesaw is 0.2 m to the left of the middle of the seesaw.

How far away from the pivot point would you need to place Box #3 (31 kg) for the seesaw to be balanced?

Would you need to place Box #3 to the left or right of the pivot for the seesaw to be balanced?

What is the net torque if Box #3 were placed at the pivot point?

How far away from the pivot point would you need to place Box #3 (31 kg) for the seesaw to be balanced?

Would you need to place Box #3 to the left or right of the pivot for the seesaw to be balanced?

What is the net torque if Box #3 were placed at the pivot point?

Explanation / Answer

A) torque is balanced so

m1*1.5- m2*1.9 + m3*x =0

8*1.5 - 13*1.9 + 31*x =0

x = (-8*1.5+13*1.9)/31 = 0.41m

B) left

C) torque = 13*9.8*1.9-8*9.8*1.5

= 124.5 Nm

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