When a solid object is completely submerged in ethyl alcohol, its apparent weigh

Question

When a solid object is completely submerged in ethyl alcohol, its apparent weight is 19.8 N and when completely submerged in water, its apparent weight is 17.6 N. Determine the volume of the object. Use 790 kg/m3 as the density of the ethyl alcohol and 1000 kg/m3 as the density of water.
_____m3

QUESTION 2

A 4.5-kg, three legged stool supports a 86-kg person. If each leg of the stool has a cross-sectional diameter of 2.6 cm and the weight of the person is evenly distributed, determine the pressure exerted on the floor by each leg.
____Pa

QUESTION 3

A 2.40 kg steel gas can holds 15.0 L of gasoline when full. What is the average density (in kg/m3) of the full gas can, taking into account the volume occupied by steel as well as by gasoline?

____ kg/m3

QUESTION 4

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How high (in m) above a user must the water level be to create a gauge pressure of 5.55 105 N/m2?

____m

PLEASE ANSWER ALL THE QUESTIONS DONT GIVE ANY WRONG ANSWERS THANKS FOR YOUR HELP !

Explanation / Answer

1. when submerged in fluid,

N = W - Fb

W = weight = rho_object V g

Fb = buoyant force = rho_fluid V g

for ethyl alcohol,

19.8 = W - (790 V g ) ....(i)

when in water,

17.6 = W - (1000 V g) .... (ii)

(i) - (ii) =>

2.2 = 210 V x 9.8

V = 1.07 x 10^-3 m^3 ......Ans

2. W = (M + m)g = (86 + 4.5)(9.8) = 886.9 N

normal reaction on each leg = W/3 = 295.63 N

cross sectio area = pi (0.026/2)^2 = 5.31 x 10^-4 m^2

P = Force / area = 295.63 / (5.31 x10^-4)

P = 556816 Pa

3. desity of gasoline = 719.7 kg/m^3

Volume = 15 x 10^-3 m^3

mass of gasoline, m = density x volume = 10.8 kg

total mass = 2.40 + 10.8 = 13.2 kg

average density = total mass / volume

= 879.7 kg /m^3

4. deltaP = rho g deltaH

5.55 x 10^5 = 1000 x 9.8 x h

h = 56.6 m

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