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ID: 1645351 • Letter: C

Question

Chrome File Edit View History Bookmarks People Window Help O@0 ) !689611. Tue Jul 18 2:46 PM Nawaf Q. E mom x Che: × C0 www.saplinglearning.com/ibiscms/modibis/view.php?id-3805086 Question 15 of 19 Due Date Points Possible: Grade Category: Description: Policies: 7/21/2017 10:00 PM 100 Graded Map Sapling Learning A basketball has a coefficient of restitution of 0.825 in collisions with the wood floor of a basketball court. The ball is dropped on such a floor from a height of 2.91 m. How high is its fourth bounce? Rubric 1 Number In You can check your answers. You can view solutions after the due date You can keep trying to answer each questionu you get it right or give up. There is no penalty for incorrect answers. For multiple-choice questions, the penalty dep on the number of choices available. eTextbook Help With This Topic Web Help & Videos Technical Support and Bug Reports + Previous O Check AnswerNext Exit Annotated Bibliog 11.docx

Explanation / Answer

coefficient of restitution = velocity of separation / velocity of approach

0.825 = v1 / v

v1 = 0.825 v ....after first bounce

after second bounce, v2 = 0.825 v1

third bounce, v3 = 0.825 v2

after 4th bounce, v4 = 0.825 v3

v4 = 0.825^4 v = 0.46325 v


Applying energy conservation,

m gh = m v^2 /2

v = sqrt(2 g h ) = sqrt(2 x 9.81 x 2.91) = 7.556 m/s

v4 = 0.46325 v = 3.50 m/s


and h = v^2 / 2 g

h' = 3.50^2 / (2 x 9.81)

h' = 0.624 m .......Ans

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