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Chrome File Edit View History Bookmarks People Window Help Mastering Chemistry: Post Lecture Homework Chapter 18 Secure https session.masteringchemistry.co 80660487 m/m Chem 132-02 Assignments Post Lecture Homework Chapter 18 Chapter 18 Non-Algorithmic Question 37 openvellum.e Chapter 18 Non-Algorithmic Question 37 Chemistry Part A urses Given the following equation, e Home N20(g NO2 (g) 3 NO(g) AG xn -23.0 kJ us Calculate AG run for the following reaction. ments 6N20(g) 6 NO2(g) 18 NO(g) -138 kJ e Tools O -23.00 kJ O -3.83 kJ Settings O 23.0 kJ 138 kJ Submit My Answers Give Up BE 93% Mon 3:45 PM Q. E Help Close Resources gle Chrome k previous l 30 of 40 l next AN DOCX story Essay S. doCX History Continue Provide Feedback ntitled

Explanation / Answer

Question 37) part A
For 1 eq of N2O and NO2 H = - 23.0 kJ
So for 6 mol H = 6 * -23.0 = - 138 kJ

Question 38) part A)
6 mol of forward reaction H = - 138 kJ. I Therefore for backward reaction H = + 138 kJ

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