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Chrome File Edit View History Bookmarks People Window Help O@· 4)) 90% Ch . Thu Jul 20 3:57 PM Nawaf QE C www.saplinglearning.com/ibiscms/modibis/view.php?id-3805087 Ddl 100 Map Sapling Learning Points Possibl Grade Categor Description Policies: 100 Race car teams will spend exorbitant money to gain even the slightest edge on their competition. At many oval race tracks, such teams even shift the location of the engine toward the inside of the turn in an effort to lower the moment of inertia of the race car with respect to an axis passing through the center of the curve 100 100 You can check You can view s You can keep t Such a car (known as a supermodified) is shown to the 100 ht. Notice the engine is placed between the left-side s. Obviously, this car is designed to turn only left. Suppose that the engine has a mass of 1030 kg and is shifted in location 60.5 cm toward the inside of the curve. Assume that the engine is relatively small in comparison to the radius of curvature of the track and that the radius of the track turn is R = 30.5 m. Calculate the absolute value of the percent change in the moment of inertia of the e caused by the shift in location. you get it right There is no pe For multiple-ch 100 100 about the center of curvature of the track on the numbe Number OeTextbook Help With Th Web Help & O Technical Su Annotated Bibliog... 1).doex 20 XIW

Explanation / Answer

Solution:

Initially the moment of inertia(before shifting of the engine):

Io = MR2

=> Io = 1030 x (30.5)2

=> Io = 958157.5 kg-m2

after the shifting moment of inertia becomes;

I = M(R-d)2

=> I = 1030 x (30.5- 0.605)2

=> I = 919291.0938  kg-m2

As we can see moment of inertia reduced.

hence;

% change = 100 x (Io - I)/Io

% change = 4.05637 %

(Approx 4%)

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