please answer question 3 Use Ohm\'s Law (AV = 1 R) to calculate the resistance R
ID: 1646986 • Letter: P
Question
please answer question 3
Use Ohm's Law (AV = 1 R) to calculate the resistance R of each resistor (R1, R2, R3), and find the equivalent resistance of the total circuit in each case. Report Attachments: printed data table (readably entered by pencil. Questions: 1. Write an equation relating ICIRCUIT to IR, I2, and IRs for each circuit (3 equations). Justify the validity of each equation by using your data for each circuit in this equation. (Show the result and comparison.) 2. Write an equation relating VCIRCUIT to VRI, VRa, and Ves for each circuit (3 equations). Justify the validity of each equation by using your data for each circuit in this equation. (Show the result and comparison.) 3. Write an equation relating RCIRCUIT to R1, R2, and R3 for each circuit (3 equations). Justify the validity of each equation by using your data for each circuit in this equation. (Show the result and comparison.) 4. Compare the values of R1, R2, and R3 found by using R AV/I in each of the 3 circuits against the values found by the ohmmeter. Use the ohmmeter as the reference in the % difference. Discuss what might cause any differences.Explanation / Answer
Circuit diagram is not provided within the question. I'll try to provide the general theory on how to compute the current and voltages.
Series connection:
Resistors are in series when same amout of current flows through them. Two identify whether two resistors are connected in series, if you pull out one resistor, if the circuit looks incomplete, i.e. not closed, then those two resistors are connected in series.
So, if a voltage V is applied to a circuit with Resistors R1, R2, R3 connected in series, same amount of current will flow through all the resistors
I1 = I2 = I3 = V/(R1 + R2 + R3)
And equivalent resistance = R1 + R2 +R3
Parallel connection:
Two resistors are in parallel when same voltage is appled accross both resistors. To identify whether they are in parallell, if you pull out one resistor the circuit is still complete/closed i.e. there are multiple pathways for current to pass through.
Total current in the circuit = I1 + I2 + I3 = V/R1 + V/R2 + V/R3 = V (R2R3 + R3R1 + R1R2)/R1R2R3
=> Equilvalent resistance = R1R2R3/(R2R3 + R3R1 + R1R2)
and I1 = R2R3/(R2R3 + R3R1 + R1R2); I2 = R1R3/(R2R3 + R3R1 + R1R2); I3 = R2R1/(R2R3 + R3R1 + R1R2)
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