A 3,000 kg car tries to make a turn at speeds much too fast for it to successful

Question

A 3,000 kg car tries to make a turn at speeds much too fast for it to successfully make the turn using only the static friction force between the road and the car's tires. To do so, the car fires a grappling hook around a structure at the corner and the tension in the cable provides the force necessary to execute the turn. We can model the turn as an arc of a circle radius 10m. If the cable breaks when its tension is greater than 10^5 N, what is the fastest speed that the car can make the turn at?

Explanation / Answer

for turning car,

T = m x centripetal acceleration

T = m v^2 / R

so T_max = m v_max^2 / R

10^5 = 3000 v_max^2 / 10

v_max = 18.26 m/s ........Ans

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.