Three resistors having resistances of 1.60 Ohm, 2.40 Ohm, and 4.80 Ohm are conne
ID: 1647707 • Letter: T
Question
Three resistors having resistances of 1.60 Ohm, 2.40 Ohm, and 4.80 Ohm are connected in parallel to a 28.0-V battery that has negligible internal resistance. Find (a) the equivalent resistance of the combination: (b) the current in each resistor: (c) the total current through the battery: (d) the voltage across each resistor: (e) the power dissipated in each resistor. Why do the lights on a car become dimmer when the starter is operated? A doubly charged ion of beryllium, Be (mass 1.51 times 10^-26 kg) traveling at 96.9 km/s enters a uniform magnetic field with magnitude 0.500 T directed perpendicular to its motion. (a) Find the radius of ion's path. (b) Sketch the motion of the ion, showing its initial velocity and the direction of the magnetic field. A 4.60-mu F capacitor that is initially uncharged is connected in series with a 7.50-k Ohm resistor and an emf source with epsilon = 245 V and negligible internal resistance. Just after the circuit is completed, what are (a) the voltage drop across the capacitor: (b) the voltage drop across the resistor: (c) the charge on the capacitor, (d) the current through the resistor? (e) A long time after the circuit is completed (after many time constants) what are the values of the quantities in parts (a)-(d)? (a) Explain the concept of the displacement current. (b) State the Ampere-Maxwell law by words. (c) Write its integral form. Fundamental constantsExplanation / Answer
1-
a) 1/Re = (1/1.6)+(1/2.4)+(1/4.8)
So , Re = 0.8 ohm
b) ir1 = 28/1.6 =17.5 Amp
ir2 = 28/2.4 = 11.67 Amp
ir3 = 28/4.8 = 5.83 Am
c) total current , i = 28/Re =28/0.8 =35 Amp
d) Voltage across each resistor will be same and equal to 28 V.
e) P1 = ir1^2*r1
P2 = ir2^2*r2
P3 = ir3^2*r3
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