Three resistors having resistances of 1.60, 2.40, and4.80, respectively, are con

Question

Three resistors having resistances of 1.60, 2.40, and4.80, respectively, are connected in parallel to a 28.0Vbattery that has negligible internal resistance. Find (a) theequivalent resistance of the combination, (b) the current in eachresistor, (c) the total current through the battery, (d) thevoltage across each resistor, and (e) thepower dissipated in each resistor. (f) Which resistordissipates the most power, the one with the greatest resistance orthe one with the least resistance? Explain why this should be.
im mostly confused on how to find the current at each resistorfor a parallel circuit. the rest i should be able to figureout...
im mostly confused on how to find the current at each resistorfor a parallel circuit. the rest i should be able to figureout...

Explanation / Answer

to find the current in each one just divide the voltage by theresistance: IR1 = 28V/1.6 IR2= 28V/2.4 IR3 =28V/4.8

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