Calculate the force needed to bring in 800 kg car to rest from a speed of 85.0 k

Question

Calculate the force needed to bring in 800 kg car to rest from a speed of 85.0 km/h in a distance of 110 M. Suppose instead the car hit a concrete abutment at full speed and is brought to a stop in 2.0 0M. Calculate the force exerted on the car and compare it with the force found in part a i.e. find the ratio of the force import be to the force in part a. Calculate the force needed to bring in 800 kg car to rest from a speed of 85.0 km/h in a distance of 110 M. Suppose instead the car hit a concrete abutment at full speed and is brought to a stop in 2.0 0M. Calculate the force exerted on the car and compare it with the force found in part a i.e. find the ratio of the force import be to the force in part a.

Explanation / Answer

Ans case A

v^2-u^2=2*a*s

0-(85*5/18)^2=2*a*110

a=-2.534 m/s^2

force applied to stop car F1=m*a=800*(-2.534)=-2027.2 N

case B

v^2-u^2=2*a*s

0-(85*5/18)^2=2*a*2

a=-139.371 m/s^2

force applied to stop car F2=m*a=800*(-139.371)=111496.8 N

F2/F1=111496.8/2027.2 =55

  

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