The graph shows the US Department of Labor noise regulation for working without

Question

The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 86.0 dB.

A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 118 dB. By what factor does that sound intensity exceed the 1.5- Hours/day intensity limits from the graph?

The graph shows the US Department of Labor noise requlation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likés to listen to musi, and plays a Boom Box at an average level of 86.0 dB. 4 2 0 85 90 100 105 Sound Level (dB) Calculate the INCREASE in the sound level from the ambient work environment level (in dB) 3.54 You are correct. Your receipt no. is 154-3926Hevous mes A student at a rock concert has a seat close to the speaker system where the average sound intensity corresponds to a sound level of 118 dB. By what factor does that sound intensity exceed the 1.5 Hours/day intensity limits from the graph? 0.00501 Submit Answer Incorrect. Tries 2/12 Previous Tries

Explanation / Answer

From the graph

at 1.5 hours/ day

intensity of sound(permissible)= 97 dB

factor increment of concert sound = 118/97 = 1.216 times ANS

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