Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

d WileyPLUS xC Chegg Study Guided Sc Physical Constants-The x x Secure https://e

ID: 1649793 • Letter: D

Question

d WileyPLUS xC Chegg Study Guided Sc Physical Constants-The x x Secure https://edugen.wleyplus.com/edugen/st UBITName Logic A WileyPLUS: MyWileyPLUSI Help I Contact Us I Leg Out WileyPLUS Halliday, Fundamentals of Physics, 100 University Physics (PHYS 107/ PHYS108/ PHYS 207) Home Read, Study & Practice Gradebook ORION Downloadable eTextbook Assignment> Open Assignment MESSAGE MY INSIRUCIOR fULL SCREEN PRINTER VERSION BACK ASSIGNMENT RESOURCES Chapter 30, Problem 014 2017 PHY108 CH 30 ]Your answer is partially correct. Try again. In Figure a a uniform magnetic field B increases in magnitude with time: as given by Figure b where the vertical axis scale is set by Bs . 11 mT end the horizontal scale is set by ts·5.1 s. A circular 022 032 040oter3aProblem l 044 conducting loop of area 11 10 4 m2 lies in the field, in the plane of thne page. The amount of charge q passing point A on the loop is given in Figure (e as a function of t, with the vertical axis scale set by qs 8.3 mc and the horizontal axis scale again set by ts = s, 1 s. what is the loop's resistance? B, t (s) t (s) Review Score 120.4 the tolerance is +/-5% Version 4.24.1.1 O Type here to search 8/13/2017 48

Explanation / Answer

Given,

Slope of the B vs t graph, dB/dt = 11 mT/5.1 s = 0.0022 T/s

Area of the conducting loop, A = 11 x 10-4 m2

Current, I = q/t = slope q vs. t graph

=  (8.3 mC)/ 5.1 s = 0.0016 A

emf, E = -(dB/dt) A = (0.0022)(11 x 10-4) = 2.42 x 10-6 volts

Resistance of the loop, R = (2.42 x 10-6)/ 0.0016 = 1.513 m ohms

Please rate my answer if you find it helpful, good luck...