Please help with all portions of the problem. Thank you!:) The efficiency of a p

Question

Please help with all portions of the problem. Thank you!:)

The efficiency of a particular car engine is 23% when the engine does 5.7 kl of work per cycle. Assume the process is reversible. What are (a) the energy the engine gains per cycle as heat Q_gain from fuel combustion and (b) the energy the engine loses per cycle as heat Q_lost. If a tune-up increases the efficiency to 35%, what are (c) Q_again and (d) Q_lost at the same work value? (a) Number Units (b) Number Units (c) Number Units (d) Number Units Click if you would like to Show Work for this question: Open Show Work

Explanation / Answer

(a)

Q (gain)

= 5.7/0.23 kJ

= 24.78 kJ

(b)

Q (lost)

= 24.78 – 5.7 kJ

= 19.08 kJ

(c)

Q (gain)

= 5.7/0.35

= 16.29 kJ

(d)

Q (lost)

= 16.29 – 5.7

= 10.59 kJ.

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.