A Honeybees acquire a charge while flying due to friction with the air. A 120 mg

Question

A Honeybees acquire a charge while flying due to friction with the air. A 120 mg bee with a charge of +13 pC experiences an electric force in the earth's electric field, which is typically 100 N/C, directed downward. What is the ratio of the electric force on the bee to the bee's weight? F/W = What electric field strength would allow the bee to hang suspended in the air? Express your answer with the appropriate units. E = What electric field direction would allow the bee to hang suspended in the air? downward upward

Explanation / Answer

F=100N/C*13*10^-12C = 1.3*10^-9 N

W = 0.12*9.81 = 1.17 N

so, F/W = 1.3*10^-9 /  1.17 = 1.1*10^-9

For suspending honeybee in the air, F = W, or 1.17 N = 13*10^-12C * E

or, E = 9.05*10^10 N/C

For electric force to be upwards for the bee having a chare of +13pC, the field should be upwards

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