A bird watcher meanders through the woods, walking 0.40 km due east, 0.65 km due

Question

A bird watcher meanders through the woods, walking 0.40 km due east, 0.65 km due south, and 2.40 km in a direction 39.0° north of west. The time required for this trip is 2.00 h.

(a) Determine the magnitude and direction (relative to due west) of the bird watcher's displacement. Use kilometers and hours for distance and time, respectively.

(b) Determine the magnitude and direction (relative to due west) of the bird watcher's average velocity.

I found the magnitude and velocity....only need the direction part.

Explanation / Answer

here,

d1 = 0.4 km i

d2 = - 0.65 km j

d3 = 2.4 * ( - cos(39) i + sin(39) j ) km

d3 = - 1.87 km i + 1.51 km j

net displacement , d = d1 + d2 + d3

d = - 1.47 km i + 0.86 km j

magnitude , |d| = sqrt(1.47^2 + 0.86^2) = 1.7 km

direction , theta = arctan(0.86/1.47) = 30.3 degree north of west

b)

average velocity , magnitude = |d| /t

magnitude = 0.85 km/h

the direction is 30.3 degree north of west

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.