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• O • Is University of South Alabama XY WileyPLUS Ahmad * G Chegg Study Guided Solution X D Travis Scott - Butterfly Ette 4 x + ca Secure | https//edugen.wileyplus.com/edugen/student/mainfruni Y NEW I Apps R WileyPLUs a Differential calculus LS University of South. Apple C iCloud Yahoo b Bing w Wikipedia F Facebook , y Twitter in LinkedIn D The Weather Channel O Yelp >> other Bookmarks wleyPLUS: MywlePLUSI Help I contact Us I Log Out WileyPLUS haiday, Fundamentals of Physics10e Calculus-based Physics I & II (PH 201-202) Home Read, Study & Practice Assignment Gradebook ORION Downloadable eTextbook Assignment > Open Assignment PULL SCREEN PRINTER VERSION BACK Dr ASSIGNMENT RESOURCES 201-6 Chapter 04, Problem 080 A 150-m-wide river flows due east at a uniform speed of 1.4m/s. A boat with a speed of 6.8m/s relative to the water leaves the south bank pointed in a direction 340 west of north. What is the (a) Dance at Boston magnitude and (b) direction of the boats velocity relative to the ground1? Give the direction as the angle of the velocity from due north, positive if to the east and negative if to the west. (c) How Ch. OS Problem I long does it take for the boat to cross the river? 056 Chapter 04, Problem (a) Number Units ((b) Number Units Chapter 05, Problem 006 (c) Number Units Review Score Review Results by Study objective LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM INII-LECTURE Question Attempts: 0 of 3 used SAVE FOR LATER SURTHE ANDER licensa Agreement privacy Policy ID 2000-201Zohn Wiley & Sons, Inc. All Rights Reserved. A Division of ohn Wiley & Sons, Inc. Version 4.24.1.20

Explanation / Answer

Here, the components of the boat's velocity with respect to the water are

along north are 6.8 m/s*cos(34) = 5.64 m/s

and along west = 6.8*sin(34) = 3.80 m/s

Therefore, relative to earth the boats velocity is

West 3.80 – 1.40 (water speed) = 2.4 m/s West and the north component is 5.64 m/s

(a) Requisite magnitude = sqrt(2.4^2 + 5.64^2) = 6.13 m/s

(b) Requisite angle = arctan(2.4/5.64) = 23.05o West of North

(c) Time to cross the river = x/v = 150 / 6.13 = 24.5 s

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