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home / study / science / physics / physics questions and answers / Two Point Charges Totaling 7.5 C Exert A Repulsive Force Of 0.065 N On Each Other When Separated ... Your question has been answered Let us know if you got a helpful answer. Rate this answer Question: Two point charges totaling 7.5 C exert a repulsive force of 0.065 N on each other when separate... Two point charges totaling 7.5 C exert a repulsive force of 0.065 N on each other when separated by 0.25 m. Q= 7.5 uC F= 0.0065 N r= 0.25 m a) What is the charge on the larger of the two charges? b) What is the charge on the smaller of the two charges? c) What is the charge on the larger charge (in magnitude) if the force is attractive? d) What is the charge on the smaller charge (in magnitude) if the force is attractive

Explanation / Answer

the repulsive force has positive sign

q + Q = 7.5 microC

or, Q = 7.5 uC - q

F = kQq / d²
Substituting known values yields
0.065 N = 9x10^9N·m²/C² * (7.50x10^-6C - q) * q / (0.25m)²
This solves to
q = µC smaller charge (A)
and Q = (7.5- ans ) µC larger charge (B)

If the force is attractive, then the force is negative, and
-0.065 N = 9X10^9N·m²/C² * (7.50X10^-6C - q) * q / (0.25m)²
leads to
q = - µC (A)
and q = (7.5- ANS) µC (B) DO THE CALCULATION AT YOUR OWN PLEASE

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