Write leaning out a window that is 6.5 m above the ground, you drop a 0.60-kg ba

Question

Write leaning out a window that is 6.5 m above the ground, you drop a 0.60-kg basketball to a friend at ground level. Your friend catches the ball at a the ground. Determine the following. (a) the amount of work done by the force of gravity on the ball 28.81 J (b) the gravitational potential energy of the ball-earth system, relative to the ground when it is released 38.22 J (c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught 9.41 J (d) the ratio of the change (PE_1 - PE_0) in the gravitational potential energy of the ball earth system to the work done on the ball by the force of gravity Delta PE/W = As the problem suggests, the change in a quantity is determined by subtracting the initial value from the final value. A negative value informs us that a decrease in the quantity of interest and a positive value indicates an increase in that quantity. How is the change in gravitational potential energy relation work done by the force of gravity?

Explanation / Answer

(d) Since the force of gravity is a conservative force, the work done on the ball by the force of gravity is the negative of the change in gravitational potential energy of the ball-Earth system.
This may be expressed as:
W = PE
which leads to the ratio
PE /W = 1.

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