A projectile is launched from the ground at an angle of 60° above the horizontal

Q: A projectile is launched from the ground at an angle of 60° above the horizontal

Solution: 1. The acceleration will be constant for the whole trajectory & will be equal to, a = g = 9.81 m/s2 2. The vector works in sequence & gets add up this way. hence; Vector X + Vector Z = Vector Y

ID: 1653106 • Letter: A

Question

A projectile is launched from the ground at an angle of 60° above the horizontal. At what point in its trajectory does it have the maximum value of acceleration? Neglect air resistance. It has the maximum value of acceleration just after it leaves the ground It has the maximum value of acceleration just before it lands on the ground Its acceleration is constant everywhere in its trajectory. It has the maximum value of acceleration halfway to the top of its trajectory. has the maximum value of acceleration at the top of its trajectory.

Explanation / Answer

Solution:

The acceleration will be constant for the whole trajectory & will be equal to, a = g = 9.81 m/s2

The vector works in sequence & gets add up this way.

hence;

Vector X + Vector Z = Vector Y

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A projectile is launched from the ground at an angle of 60° above the horizontal

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