xpert TA J Human-x Secure https//us138ok theexperttacomcommon/TakeT | Homework \
ID: 1653248 • Letter: X
Question
xpert TA J Human-x Secure https//us138ok theexperttacomcommon/TakeT | Homework "2 Begin Date: yy2017 12.00 UU AM-Due Date: y 12/JU17 12.0000 AM End l'ate: y2/JUIT12AREDE, AM (7%) Problem 6: Three charges are located as shown in the figure, with values - 3./1 1016 C. 923x 10'16C,9375×10.)6 C. The charges are separated by d,-3.4 × 104 m and d2-2.5×10-6 m. q, d, enment Status 9 Specific Feedback s available the Feedback button below to view Ctheexpertta.com ere may also be hints available 50% Part (a) What is the force ofq2 on 91 thex direction, F Glve your answer m newtons and recall k8988 x 102 N m2/C2 50% Part (b) what is the force of q3 on q, in the y direction, F. Give your answer in newtons. Close Com con e ed S Completed Grade Summary Completed I [ Poteaual 100 | | tan() ( 819 Submissions Attempts renaming: (0s per attempt) detailed vien Partial sinO cos() acoso acotan0 sinho 09% cosh) tanb)cotanh() . Degrees Radians Subenit Hint Feedback I give up Hints: 0 Feedback: 0% deduction per feedback 1033 PM 9/10/201Explanation / Answer
The force between two charges is given by:
F = k q1q2/r^2
where, k is the constant, q1q2 are the magnitudes of charges,r is the distance between the charges.
a)the force along x is only due to q2
Fx = k q1q2/d1^2
Fx = 8.99 x 10^9 x 3.1 x 10^-16 x 1.8 x 10^-16/(3.4 x 10^-6)^2 = 4.338 x 10^-11 N
Hence, Fx = 4.338 x 10^-11 N
b)Fy = k q1q3/d2^2
Fy = 8.99 x 10^9 x 3.1 x 10^-16 x 5.75 x 10^-16/(2.5 x 10^-6)^2 = 2.564 x 10^-10 N
Hence, Fy = 2.564 x 10^-10 N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.