IP In a friendly game of handball, you hit the ball essentially at ground level

Question

IP In a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall with a speed of 18 m/sat an angle of 34 above the horizontal.

Part A

What are the magnitude and direction of the ball's velocity when it strikes the wall 4.0 m away?

Express your answer using two significant figures.

Part B

Express your answer using two significant figures.

= ________ to the horizontal

Part C

Has the ball reached the highest point of its trajectory at this time?

Explanation / Answer

Solution:

Horizontal component of the velocity = Vx and vertical component = Vy

Vx = Vcos = 18*cos34° = 14.9 m/sec
t = d/Vx = 4/14.9 = 0.268 sec
Vy = Vsin - g*t

=> 7.44 m/s

Net Velocity = [Vx²+Vy²] = 16.65 m/s
= arctan[Vy/Vx]

=> 26.5° above horizontal

Now, At maximum height final velocity = 0

using V = U + a*t

0 = 7.44 + (-9.8) t

t = 7.44/9.8 = 0.76 seconds

So it takes 0.76 seconds to reach at maximum height so the answer for Part C is NO

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