IP In 1926, Albert Michelson measured the speed of light with a technique simila

Question

IP In 1926, Albert Michelson measured the speed of light with a technique similar to that used by Fizeau. Michelson used an eight-sided mirror rotating at 528 rev/s in place of the toothed wheel, as illustrated in the figure.The distance from the rotating mirror to a distant reflector was 35.5 km. The light completed the 71.0-km round trip in the time it took the mirror to complete one-eighth of a revolution.
Suppose the distance to the fixed mirror in the figure is decreased to 22.5 km.


http://session.masteringphysics.com/problemAsset/1126512/4/Walker4e.ch25.Pr092.jpg


Part b)

Find the required angular speed, assuming the speed of light is 3.00 *10^8 m/s.
omega = _______ rev/s


I was able to solve part a by myself I just don't understand part b please help!

Explanation / Answer

Since d = vt, the total distance the light will travel is 45 km,   or 45000 m

The time required to do that trip is

t = d/v

t = (45000)/(3 X 108)

t = 1.5 X 10-4 sec

Finally, since it will only make 1/8th of a revolution which is .125 revolutions in that time, we can set up...

.125 rev/1.5 X 10-4 sec

We get 833.33 rev/sec

Since we only have 3 significant figures in the question, I guess you would call it 833 rev/sec

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.