6-9 Electric Charge QUESTIONS 1) Answer the following questions. Give a detailed

Question

6-9 Electric Charge QUESTIONS 1) Answer the following questions. Give a detailed explanation for each response. a. Can an object with a positive net charge attract a neutral object? b. Can a neutral object attract an object with a positive net charge? 2) Examine the representation of the charged plastic rod in Figure 21.2 on page 611 (10th ed) of your text. Is this an accurate representation of the charges present in the rod? If so, explain why. If not, explain why not and propose a more accurate figure. 3) A longhaired cat is in need of some grooming. When it is combed, the cat looses 8x 10 electrons. a. What is the sign and magnitude (in Coulombs) of the net charge on the cat? b. On the comb? c. It is reasonable to treat the cat as though it is made of water (18 g/mol, remember that are 6x10 molecules in a mole). Also assume that it has a mass of 9 kg Approximately what fraction of the cat's electrons are removed to create this net charge? Comment on the size of this fraction. 4) 1 x 10° electrons are removed from a penny (2.5g). The same number is removed froma quarter (5.67g). Compare the magnitudes of the net charges on the two objects. 5) Shown below are three fixed charges 2ms uC a. Find the net force on the 4uC charge. Show your calculations. Now put an imaginary box around the two charges on the left as shown. Treat these charges as one object. What is the net charge on this object? b. What is the force (magnitude and direction) exerted on this object by the 4uC charge? If the magnitude is zero state that explicitly, if not, explain how you determined y answer. c. Is your answer to part (c) consistent with Newton's Third Law? If not, resolve the inconsistency d.

Explanation / Answer

1) (a) yes, if neutral object is made of conducting material.

(B) yes, if neutral object is made of conducting material.

3) (a) Q = n e

Q = (8 x 10^10) (1.6 x 10^-19)

Q = 1.28 x 10^-8 C

electrons are missing so cat is positively charged.

(b) comb is negatively charged.

Q = - 1.28 x 10^-8 C

(c) n = 9 x 10^3 / 18 = 500 mol

total number of electron = 10 x 500 x 6 x 10^23

= 3 x 10^27 electrons

fraction = 2.67 x 10^-17

this is a very small number.

4) same of number of electrons are removed hence magnitude of charge on both will be same.

q = (1 x 10^10) (1.6 x 10^-19)

q = 1.6 x 10^-9 C

Related Questions

Navigate

• Browse (All)
• Browse 6
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.