I used a kinematic equation to find the time for it to fall 1.2m =.49s from here

Question

I used a kinematic equation to find the time for it to fall 1.2m =.49s
from here, I don't know where to go. As far as relative motion, I have the bike to the landing spot and the landing spot to the bike. Does the paper have a relative motion. please help.

A paperboy is riding his scooter at a constant speed of 5.30 m/s. He wishes to throw a newspaper directly horizontally from a height of 1.20 m so that it lands exactly on a spot on the ground that will be 2.20 m to his left when he passes it. Where should the boy be when he throws the paper, and with what horizontal speed should he throw it? vill band with whizontal speed s

Explanation / Answer

Consider the vertical motion of the paper under gravity.

sv = uvt + gt2/2

=> 1.20 = 0 + (9.81 * t2 / 2)

=> t = (1.20 * 2 / 9.81)1/2 = 0.495 s

Let the distance of the paperboy from the road directly across the paper be 'x'. Then,

x = 5.30 * 0.495 = 2.62 m

Speed at which the paper is thrown, v = 2.20 / 0.495 = 4.44 m/s

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